์ด๋ ๊ฒฐ๊ณผ๋ ๊ฐ์ฒด์ ID ์ ๋ํด ์ค๋ฆ์ฐจ์ ์ ๋ ฌํด์ฃผ์ธ์.
ํ์ด
select p.ID, ifnull(c.cnt, 0) as CHILD_COUNT
from ECOLI_DATA p leftjoin
(
select PARENT_ID, count(ID) as cnt
from ECOLI_DATA
groupby PARENT_ID
having PARENT_ID isnotnull
) c on p.ID = c.PARENT_ID
orderby ID